60p^2=48-32p

Solution for 60p^2=48-32p equation:

60p^2=48-32p

We move all terms to the left:

60p^2-(48-32p)=0

We add all the numbers together, and all the variables

60p^2-(-32p+48)=0

We get rid of parentheses

60p^2+32p-48=0

a = 60; b = 32; c = -48;
Δ = b2-4ac
Δ = 322-4·60·(-48)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-112}{2*60}=\frac{-144}{120}
=-1+1/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+112}{2*60}=\frac{80}{120}
=2/3
$